# Shouldn't the input state of Deutsh-Jozsa's algorithm look like $|0\rangle^{\otimes n}\otimes |1\rangle$ rather than $|0\rangle^{\otimes n}|1\rangle$?

According to this wikipedia page the initial state in Deutsch–Jozsa algorithm is written as follows: $$|0\rangle^{\otimes n} |1\rangle$$

shouldn't it look like this?:

$$|0\rangle^{\otimes n} \otimes |1\rangle$$

This is just a convention. People tend to write $$|01 \rangle$$ instead of $$|0 \rangle \otimes |1\rangle$$, but they mean the same thing. In this case, $$\overbrace{|0\rangle \otimes |0\rangle \otimes \cdots \otimes |0\rangle}^{n \ \ times} \otimes|1\rangle = |0\rangle^{\otimes n} \otimes |1\rangle = |0\rangle^{\otimes n} |1\rangle$$