6
$\begingroup$

I have trouble understanding two equations in the Nielsen & Chuang textbook. Suppose we perform a measurement described by the operator $M_m$. If the initial state is $|\psi_i\rangle$, then the probability of getting result m is

$$ p(m|i)=\langle\psi_i|M_m^\dagger M_m|\psi_i\rangle. $$

The form of this equation looks like the overlap between two states, but I'm not exactly sure what $ M_m|\psi_i\rangle$ means? Is this relevant to the projection operator?

Also, given the initial state $|\psi_i\rangle$, the state after obtaining the result m is

$$ |\psi_i^m\rangle = \frac{M_m|\psi_i\rangle}{\sqrt{\langle\psi_i|M_m^\dagger M_m|\psi_i\rangle}}. $$

Why is this the case?


Cross-posted on physics.SE

$\endgroup$
7
$\begingroup$

Measurement postulate

The statement you are asking about is a postulate of quantum mechanics, so it cannot be mathematically derived from other facts in the theory. Instead, it is justified by its agreement with observation in the sense that it allows us to mathematically describe every measurement we can perform in practice.

Intuitive interpretation

The meaning of $M_m|\psi_i\rangle$ is that this is the unnormalized post-measurement state. The measurement postulate provides a prescription for computing two quantities: measurement outcome probability $p(m|i)$ and post-measurement state $|\psi_i^m\rangle$. Both are derived from $M_m|\psi_i\rangle$.

Specifically, the measurement outcome probability $p(m|i)$ is the squared norm of $M_m|\psi_i\rangle$

$$ p(m|i) = \| M_m|\psi_i\rangle \|^2 = \langle \psi_i | M_m^\dagger M_m|\psi_i\rangle. $$

The reason it looks like state overlap is because the norm is the defined in terms of the inner product as $\| |\psi\rangle \| = \sqrt{\langle\psi|\psi\rangle}$.

The post-measurement (or collapsed) state is the normalized $M_m|\psi_i\rangle$

$$ |\psi_i^m\rangle = \frac{M_m|\psi_i\rangle}{\| M_m|\psi_i\rangle \|} = \frac{M_m|\psi_i\rangle}{\sqrt{\langle \psi_i | Mm^\dagger M_m|\psi_i\rangle}}. $$

Relationship to projective measurement

This form of measurement postulate defines a more general type of measurement than the projective measurement. The latter is a special case in which $M_m$ are projectors. In this case, $M_m^\dagger = M_m$ and $M_m^\dagger M_m = M_m$ and we recover the familiar projective measurement. In general though the measurement operators $M_m$ do not need to be projectors.

A prominent example of non-projective measurements that can be described using the general form of the postulate are the POVM measurements. However, even though the general form subsumes the projective measurement, it is possible to implement the general measurement using projective measurement, unitary evolution and auxillary subsystems, see p.94 in Nielsen & Chuang.

$\endgroup$
2
  • 1
    $\begingroup$ Thank you so much, that's super helpful:) $\endgroup$ – ZR- Jan 18 at 2:02
  • $\begingroup$ You're welcome! I'm glad you found it helpful! :-) $\endgroup$ – Adam Zalcman Jan 18 at 2:05

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.