Quantum teleportaion seems to occuring without entanglement in circuit (what's wrong)

Please, pardon the caption. No intention of making new theories. I am a bit confused about the quantum teleportation. I missed a hadamard gate before CNOT gate for creating the EPR pair. But the circuit seems to bee working and copying q0 to q2.

Circuit without entanglement and initial Hadamard gate:

Results consistent with q0 wave function: This is measurement of q2 for multiple shots

I am new to quantumn mechanics domain, any guide or help would mean a lot. Thank you for your help :).

• It seems that there is a missing Hadamard on qubit q55_1 necessary to create Bell state. In this configuration second and third CNOT work as fan out and simply "copy" state from q55_0 to q52_0. Jan 15 at 15:37
• Yeah exactly my point, this is not the correct teleportation protocol. But how do we end up having a measurement consistent with teleportation? Jan 15 at 15:58
• @SayanDey Are you sure that is the right result? Also, without the Hadamard gate in front of q_551 you can essentially removed the CNOT between q_551 and q_552 since they always start in the $|0\rangle$ state so a CNOT here would not do anything Jan 15 at 16:13
• @KAJ226 I understand your point. Also I am not claiming the states are same. But one thing to be precise, if you see the wave function in the 1st pic, it is consistent with their squared value which are 3/4 and 1/4 shown as probabilities in the second pic. Wave function belongs to q550 and probabilities belong to q552. Jan 15 at 16:44
• I'll second KAJ226 - I don't think this output can match this circuit, since no gates act on q2 that can put it in superposition. Are you quite sure the histogram is built on this circuit for qubit q2? Jan 15 at 18:47

$$a * a^{\ast} = (\alpha + i \beta) * (\alpha - i \beta) = \alpha^2 + \beta^2$$