# In Nielsen and Chuang, how can $\frac{1}{2(e-1)}$ result from $\frac12\int_{e-1}^{2^{t-1}-1}dl\frac{1}{l^2}$?

From Nielsen and Chuang's book: $$\textit{Quantum computation and quantum information}$$, how can (5.34) equal (5.33)? I.e.

$$\dfrac{1}{2} \int_{e-1}^{2^{t-1}-1} dl \dfrac{1}{l^2} = \dfrac{1}{2(e-1)}.$$

• Probably a typo, it should read leq again (note that t>1). Nov 29 '20 at 14:36
• As @M.Stern commented, this is probably a typo as $$\dfrac{1}{2} \int_{e-1}^\infty \dfrac{1}{l^2} dl = \dfrac{1}{2(e-1)}$$ Nov 29 '20 at 18:57
• Nielsen and Chuang errata: michaelnielsen.org/qcqi/errata/errata/errata.html You can check here. Nov 30 '20 at 7:55
• please use mathjax to write down the equation in the post
– glS
Nov 30 '20 at 10:46
• @M.Stern: I see. Just to inform you, it is also wrong in my 10th aniversary edition (2016). Nov 30 '20 at 18:45