From my understanding, a qubit is entangled when the state of one qubit depends on the other, and vice versa. Can the following bell states have probability amplitudes other than 1/2 and still be entangled?:
$ |\Phi^\pm\rangle = \frac{1}{\sqrt{2}} (|0\rangle_A \otimes |0\rangle_B \pm |1\rangle_A \otimes |1\rangle_B) $
${\displaystyle |\Psi ^{\pm }\rangle ={\frac {1}{\sqrt {2}}}(|0\rangle _{A}\otimes |1\rangle _{B}\pm |1\rangle _{A}\otimes |0\rangle _{B})} $
For example, is it possible to have bell pairs with probability amplitudes that are not $ \dfrac{1}{\sqrt{2}}$, but rather something like this: $|\Psi\rangle = \frac{\sqrt{3}}{2} (|00 \rangle + \frac{1}{2} |11\rangle)$