# What would be measured if you measure two entangled qubits at exactly the same time?

What would be measured if you measure two entangled qubits at exactly the same time?

• Welcome to QCSE. Can you edit your question to provide more clarification on what you are asking? If Alice and Bob share two entangled qubits, e.g. $\frac{1}{\sqrt 2}(\vert 0_A0_B\rangle+\vert 1_A1_B\rangle)$, and Alice and Bob measure at the "same" time, it's the same as measuring at "different" times - they will either simultaneously get $0$ or $1$. Sep 13 '20 at 23:39
• Sure, I think that I am trying to ask, would you get the same measurement or a different one? Because quantum entangled particles correlate to each other which means that you can deduce one thing from the other. So if you measure two entangled particles, at exactly the same time wouldn't the result be random (the two qubits would randomly choose between zero or one even if they are entangled meaning that it would be luck if you measure them the same)? Sep 15 '20 at 1:14
• So if the quantum bit is separated by 1 light second. And you measure it is impossible to get the exact same answer, unless there is a communication travelling faster than the speed of light. Sep 15 '20 at 1:17