I am referring to the article Advanced Topics in Quantum Information Theory exercise 4 and to the MS Quantum Kata MS-Quantum-Kata which describes a solution for the Mermin–Peres Magic Square Game. I could follow the article and do all the maths for myself until the end of the article. Unfortunately the article ends with

... Following the hint, we consider two maximally entangled states shared between Alice and Bob:$$|Ψ〉_{AB}=1/√2(|00〉_{A_1B_1}+|11〉_{A_1B_1})⊗1/√2(|00〉_{A_2B_2}+|11〉_{A_2B_2})$$ It is then easy to check by using $$1/√2(|00〉+|11〉) =1/√2(|\phi^x_0\phi^x_0〉+|\phi^x_1\phi^x_1〉) =1/√2(|\phi^y_0\phi^y_1〉+|\phi^y_1\phi^y_0〉)$$ where $|0,1〉$ are the eigenvectors of $σ_z$ and where $|φ^{x,y}_j〉$ denote the eigenvectors of $σ_x$ and $σ_y$ as in the solution to the last exercise (with eigenvalues ±1 each), that the compatibility condition is indeed satisfied.

Unfortunately for me it is not easy to check, I spent multiple nights to try this, but I don't get it done.

  1. Can anyone show me how this check looks like? What is the math behind it?
  2. The algorithm states that Alice (and Bob) are performing multiple measurements on their qubits for all observables $M_{x,y}$ in her row (in his column).
    I don't understand why this makes sense: After the first measurement the quantum state has collapsed (or could have at least), why does it make sense to do additional measurements? I know there is something called "phase kick-back" that kicks the phase into the control bit if I use "Controlled Operations", is that something that is used here? How exactly?
  3. Is "Phase Kickback" only a mathematical trick or do physical systems really behave like this? Is there an easy to understand sample maybe, for a non-physic, non-mathematic guy (just a software dev)?

Thanks a lot for any help or hints.

  • 1
    $\begingroup$ So you have problems to check this identity: $1/√2(|00〉+|11〉) =1/√2(|\phi^x_0\phi^x_0〉+|\phi^x_1\phi^x_1〉) =1/√2(|\phi^y_0\phi^y_1〉+|\phi^y_1\phi^y_0〉)$? $\endgroup$
    – draks ...
    May 2, 2020 at 21:16
  • $\begingroup$ @draks... No, I see the identity, but I dont know how that helps me to see that the condition is satisfied. $\endgroup$ May 2, 2020 at 23:30

1 Answer 1


Not an answer yet, but to long for comment: Alice and Bob share two entangled pairs. Now look only at Alice's. The last line gives the state that only one of'em has: $$\frac1{\sqrt 2}(|00〉+|11〉) =\frac1{\sqrt 2}(|\phi^x_0\phi^x_0〉+|\phi^x_1\phi^x_1〉) =\frac1{\sqrt 2}(|\phi^y_0\phi^y_1〉+|\phi^y_1\phi^y_0〉).$$ You can see that when you trace out Bob. Now all hermitian measurement operator in one row/column commute, which means that they share eigenvectors. So after the collapse at the first measurement, subsequent measurement along communting operators don't alter the state anymore, since they are already eigenstates. I think you have to check that the measured value is the same at the coincident site...

  • $\begingroup$ Sorry for the late response. I have the feeling that explanation will help me, but I need to redo the maths. I am not so used to work with eigenstates / eigenvalues, I need to go through in small steps to see if I really understand it now. Thanks a lot in advance, and I hope I might come back to you if I have questions... $\endgroup$ May 7, 2020 at 20:39

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