In HHL algorithm, for subroutine involving controlled rotation, after applying $R_y(\theta)$, where $\theta=2\sin^{-1}\left(\frac{C}{\lambda}\right)$ to the ancilla, the state changes to $\sqrt{1-\frac{C^2}{\lambda^2}}|0\rangle+\frac{C}{\lambda}|1\rangle.$
Question
If $\lambda=1$, then by $\sqrt{1-\frac{C^2}{\lambda^2}}|0\rangle+\frac{C}{\lambda}|1\rangle$ and choosing $C=1$, we get $\theta=\pi$. For $\lambda=2$, $\theta=\frac{\pi}{3}.$ So in general, for each $\lambda$, correspondingly there's a different $\theta$. Since we don't know eigenvalues a priori, how do we account $\theta $s for superpositon of eigenvalues?
With respect to the circuit here on page 5, I don't understand how the controlled rotation part works. Will this circuit work when I choose a hermitian matrix $A_{4\times 4}$ such that, one of it's eigenvalues, $\lambda_j=10\neq 2^i,i \in \mathbb{Z}$ ?