How to construct Control-Z with square root of swap(up to some single qubit operations)? In some papers it just directly mention that it's possible but didn't tell how to do.
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2 Answers
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Found by just trying stuff in Quirk:
answered Mar 10, 2020 at 17:38
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To add to the circuit by @Craig, the reason why papers tend to mention that some gate is obtainable by $\sqrt{swap}$ upto a few single qubit gates is because the set that contains the $\sqrt{swap}$ gate and all the one qubit gates is considered to be a universal set of quantum gates. That is, by just using just the $\sqrt{swap}$ gate and some single qubit gates, it is possible to construct any single or multi qubit quantum gate.
