Timeline for What is the difference between superposition of $|0\rangle$ and superposition of $|1\rangle$ at physical level?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Nov 10, 2019 at 5:08 | comment | added | bipul kalita | "The Hadamard gate can also be expressed as a 90º rotation around the Y-axis, followed by a 180º rotation around the X-axis " found in this page quantum-inspire.com/kbase/hadamard this makes sense now. It works. But we have to imagine it in a 3d sphere. | |
| Nov 9, 2019 at 22:43 | comment | added | Mark Spinelli | @MartinVesely you're right, let me think... | |
| Nov 9, 2019 at 22:35 | comment | added | Martin Vesely | Since Hadamard gate is inversion of itself, i.e. $HH=I$ I would expect that the rotation will be zero. However, when Hadamard causes rotation by 45 degrees, two Hadamards applied in row should lead to rotation by 90 degress resulting in changing state $|0\rangle$ to $|1\rangle$. But apparently this is not the case. Could you please explain this? | |
| Nov 9, 2019 at 19:13 | comment | added | bipul kalita | feeling better now. I think I should forget about "superposition" word, it's better and meaningful when I call it , "a photon with probabilities". So, how much the Hadamard gate will rotate if I apply twice in both |0> and |1> . Because Hadamard is also reversible . | |
| Nov 9, 2019 at 18:35 | comment | added | Mark Spinelli | When you equate horizontal polarity with $\vert 0\rangle$, such a Hadamard gate (please capitalize for now) acting on a photon having horizontal polarity would rotate the polarity of the photon by $45^circ$. If you had equated vertical polarity with $\vert 0\rangle$ instead, then the Hadamard gate would correspond to rotating the polarity by $135^\circ$. | |
| Nov 9, 2019 at 18:24 | comment | added | bipul kalita | So if a photon has 20% chance of being in horizontal polarization , can i call it superposition ? Then if a photon has 100% chance to be in horizontal polarization then let's call it |0>, if i apply hadamard operation in this |0> then what it would do? | |
| Nov 9, 2019 at 18:00 | history | answered | Mark Spinelli | CC BY-SA 4.0 |