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Dec 21, 2023 at 7:00 comment added Martin Vesely Just to add to QFT. If input qubits are all in state $|0\rangle$, then QFT and application of Hadamard on each qubit are equivalent. This is the case in Short or HHL algorithms.
Dec 21, 2023 at 5:44 vote accept Ryan Wang
Dec 21, 2023 at 5:42 vote accept Ryan Wang
Dec 21, 2023 at 5:42
Dec 20, 2023 at 20:29 history answered Mark Spinelli CC BY-SA 4.0