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Nov 8, 2022 at 14:27 answer added Lluvio Liu timeline score: -1
Aug 29, 2020 at 19:16 vote accept Attila Kun
Aug 29, 2020 at 6:58 answer added DaftWullie timeline score: 4
Aug 29, 2020 at 3:20 comment added Attila Kun Thanks, that answers my question. I tried proving $|i\rangle\!\langle i|\otimes\lvert j\rangle\!\langle j\rvert=\lvert i,j\rangle\!\langle i,j\rvert$ and managed to convince myself of its truth by expanding the terms into matrices/vectors and see what gets multiplied by what, but I'm wondering if there's a "nicer" way to do this. I tried looking at the definitions in Nielsen & Chuang (10th edition) page 73 but couldn't find anything useful, which is weird because the book usually introduces the necessary identities prior to the exercises.
Aug 28, 2020 at 22:35 comment added glS it's just a redefinition. More precisely you should write $|k\rangle=|i,j\rangle$. The only identity you are using is $|i\rangle\!\langle i|\otimes\lvert j\rangle\!\langle j\rvert=\lvert i,j\rangle\!\langle i,j\rvert$
Aug 28, 2020 at 22:33 history edited glS CC BY-SA 4.0
deleted 19 characters in body
Aug 28, 2020 at 20:34 history asked Attila Kun CC BY-SA 4.0