# Timeline for Mitigating the noise in a quantum circuit

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Mar 13 '20 at 13:46 comment Thank you so much. I accepted your answer :-)
Mar 13 '20 at 13:28 comment If I understood it correctly, you put $X$ on qubit $q_1$. If there is no noise, the result should be $10$ always. Accroding to results you posted, it seems that after error correction probability of measuring $10$ increased. Probability of measuring $00$ which is result of spontaneus relaxation from state $10$ decreased significantly. So you are on good way to correct for noise. Of course, you are not able to eliminate noise completely but this is OK as quantum systems are probabilistic.
Mar 13 '20 at 12:23 comment Following your answer and the comment by @DavitKhachatryan, I have prepared the code in the question edit. Is the achieved result what I should expect in practice?
Mar 10 '20 at 19:20 history answered